AW: VMs: Char repetition redux

["Anders, Claus" <Claus.Anders@xxxxxxxxxxxxx>]

This is 1% (relative frequency) not probability (which would be 0.01).
Too show an example:
1.62236 7 o-o 1766 108854
1.78965 6 o-o 2354 131534
1.82273 5 o-o 2811 154219

The number of all  <char>-<char> pairs with a distance of 5(6,7) is 154219(131534,108854).
The count for an  o-o pair with a distance of 5(6,7) is 2811(2354,1766).
The rel. Frequency is 1.8%(1.%,1.6%) 

Regarding o-o, the peak is closer to 5.5 than to 6.5, but still better in the average range than before (was 3).

I'll hope, you can understand the method a little better.

Tanoshinde kudasai
Claus

-----Ursprüngliche Nachricht-----
Von: elvogt@xxxxxxxxxxx [mailto:elvogt@xxxxxxxxxxx] 
Gesendet: Donnerstag, 23. September 2004 13:39
An: vms-list@xxxxxxxxxxx
Betreff: Re: VMs: Char repetition redux


Zitat von "Anders, Claus" <Claus.Anders@xxxxxxxxxxxxx>:

> ...
> Freq. Dist Char. pair
> ...
> 1.61051 7 o-o
> 1.70724 6 o-o
> ...
> (the relative frequency is the quotient of all occurences of a pair 
> with the given distance divided by the number of all occurences of the 
> same distance).
> 

You certainly aren't saying that you got probabilities > 1 for some distance 
pairs? In this case I'd have serious doubts about your values/hypotheses.

OTOH, it's more probable that I misinterpret your data... could you shed some 
light?

   Elmar


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